A carousel with a 45foot diameter makes 3 revolutions per mi
A carousel with a 45-foot diameter makes 3 revolutions per minute.
(a) Find the angular speed of the carousel in radians per minute. (Round your answer to two decimal places.)
 18.85 radians per minute
 
 (b) Find the linear speed (in feet per minute) of the platform rim of the carousel. (Round your answer to two decimal places.)
______?___ Feet per minute
Solution
1 revolution is 2 radians.
3 revolutions = 6 radians, or 18.85 radians/min
Angular Speed : 18.85 radians/min
C = 2r = 2(45 ft) = 282.6 ft
3 revolutions 847.8 ft
847.8 ft / min will be the linear velocity.
Post a comment if you have a doubt.
Rate me well if you like the solution.

