Please help answering the following questionsSolution1 Consi

Please help answering the following questions:

Solution

1.

Consider:

Thus,      
      
E(x) = Expected value = mean =    1   [ANSWER]

Var(x) = E(x^2) - E(x)^2 =    1   [ANSWER, VARIANCE]

x P(x) x P(x) x^2 P(x)
0 0.4 0 0
1 0.3 0.3 0.3
2 0.2 0.4 0.8
3 0.1 0.3 0.9
Please help answering the following questions:Solution1. Consider: Thus, E(x) = Expected value = mean = 1 [ANSWER] Var(x) = E(x^2) - E(x)^2 = 1 [ANSWER, VARIANC

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