Two converging lenses having focal lengths of f1 10 cm and
Two converging lenses having focal lengths of f1 = 10 cm and f2 = 21 cm are placed 50 cm apart as shown in Figure. The final inverted image is to be located between the lenses at the position 37 cm to the right of the first lens. How far (in cm) to the left of the first lens should the object be positioned? Express the answer (numerical value only) with one decimal place.
Solution
1/do + 1/di = 1/f
di = -(50 - 37) = -13 cm [ as the image is to the left of the lens ]
1/do = 1/21 + 1/13
do = 8.03 cm
The object for f2 is the image for f1 or (50 - 8.03 = 41.97) to the right of f1
1/do + 1/di = 1/f
1/do + 1/41.97 = 1/10
do = 13.13 cm [ to the left of f1 ]
