if tan theta 724 and cot beta 34 for a second quadrant angl

if tan theta= -7/24, and cot beta = 3/4, for a second quadrant angle theta, and a third quadrant angle beta, fine sin(theta+beta)

tan = -7/24 (Q-II)

sec = sqrt[1 + tan^2 ] = -25/24

cos = 1/sec = -24/25

sin = sqrt[1 - cos^2 ] = 7/25

cot = 3/4 (Q-III)

csc = sqrt(1 + cot^2 ) = -5/4

sin = -4/5

cos = sqrt[1 - sin^2 ] = -3/5

sin( + ) = sin cos + cos sin = (7/25)*(-3/5) + (-24/25)*(-4/5) = -21/125 + 96/125 = 3/5