A variable has a normal distribution with a mean of 170 and
A variable has a normal distribution with a mean of 170 and a standard deviation of 10.
5. The most extreme 5% of score are all below _____ or above ____.
6. What percent of scores are below x=183?
7. What score is needed to be in to 1% of the distribution?
Solution
mu =170
sigma = 10
Z score for 95% = 1.96 both sides
Hence X should be 170-1.96*10, 170+1.96*10
=(150.4, 189.6)
The most 5% extreme are either below 150.4 or above 189.6
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P(X<183) = P(Z<1.3) = 0.9032
Hence 90.32%
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To be in 1% of the distribution
z score should be below -2.58 or above 2.58
Hence x should be below 170-(2.58*19.6) or above 170+2.58*19.6
below 119.432 or above 220.568
