Homework SourseA bag contains 9 red 10 orange 10 green jelly beans What is
A bag contains 9 red, 10 orange, 10 green jelly beans. What is the probability of reaching into the bag and randomly withdrawing 11 jelly beans such as the number of red ones is 1, the number of orange ones is 5, and the number of green ones is 5?
A bag contains 9 red, 10 orange, 10 green jelly beans. What is the probability of reaching into the bag and randomly withdrawing 11 jelly beans such as the number of red ones is 1, the number of orange ones is 5, and the number of green ones is 5?
Solution
We choose 1 of 9 red, 5 of 10 orange, and 5 of 10 green when we select 11 from the 9+10+10 = 29 jelly beans.
Thus, the probability is C(9,1)C(10,5)C(10,5)/C(29,11) =
9 * 252 * 252 / 20030010 =
13608/476905 =
0.0285339847558738
