A Here we will simulate an experiment using a standard curve
A) Here, we will simulate an experiment using a standard curve to estimate the concentration of a newly discovered molecule, Hollinase, in an unknown sample. The concentration of molecules can be given as a mass per volume, when you don\'t know the formula weight. In the chart below, calculate the amount of standard Hollinase at a known concentration (0.5 ug/ul) and water to combine to make l ml of solution at each concentration listed. If you need a reminder about how to do this, see the appendix \"Biological Math\".

Solution
Let’s calculate for 1ng/uL
Stock = 0.5ug/uL = 500 ng/uL
Required = 1ng/uL
required Volume = 1 mL =1000uL
C1V1= C2V2
(stock) (required)
V1=C2V2/C1
V1 = (1ng/uL X 1000 uL)/ 500 ng/uL
= 2 uL
2 uL of stock + 998 uL of diluent
Sol con ng/uL
vol of Hollinase uL
Vol of H2O uL
Total vol mL
0
0
1000
1
1
2
998
1
2.5
5
995
1
5
10
990
1
10
20
980
1
==
| Sol con ng/uL | vol of Hollinase uL | Vol of H2O uL | Total vol mL |
| 0 | 0 | 1000 | 1 |
| 1 | 2 | 998 | 1 |
| 2.5 | 5 | 995 | 1 |
| 5 | 10 | 990 | 1 |
| 10 | 20 | 980 | 1 |

