Given 2 parallel lines cut by a transversal solve for x and

Given 2 parallel lines cut by a transversal, solve for x and all 8 angles.

(a) Due to alternate angle -----

5x+30 = 8x-15

8x-5x = 30+15

3x = 45

x = 15

So, angle --- 5x+30 = 5(15)+30 = 105

8x-15 = 8(15) - 15 = 105

(b) A little difference in b.

Here ---

5x+18 = 180 - (8x+16)

5x+18 = 180-8x-16

5x+8x = 180-16-18

13x = 146

x = 146/13