A constant horizontal pull acts on a sled on a horizontal fr

A constant horizontal pull acts on a sled on a horizontal frictionless ice pond. The sled starts from rest. When the pull acts over a distance x, the sled acquires a speed v and a kinetic energy K. If the same pull instead acts over twice this distance: The sled\'s speed will be v squareroot 2 and its kinetic energy will be K squareroot 2. The sled\'s speed will be v squareroot 2 and its kinetic energy will be 2K. The sled\'s speed will be 2v and its kinetic energy will be K squareroot2. The sled\'s speed will be 2v and its kinetic energy will be 2K. The sled\'s speed will be 2v and its kinetic energy will be 4K.

Solution

Let the force is F.

So worl done by force = F*x

SO KE= F*x

Vlocity = (2*F*x/m)^1/2

NOw if distance is doubled then KE would be doubled and V would be 2^1/2 times. so second option is answer