Heat Transfer 10 square fins with conductivity 50 WmK and si

Heat Transfer: 10 square fins with conductivity 50 W/mK and side length 5.0mm are installed on a 10cm ×10cm surface whose base is kept constant at 275C. The length of each fin is 8cm, and the fins are exposed to air at 35C with convection heat transfer coefficient 90 W/m²K.

Calculate:

(a) The fin efficiency, _f

(b) The overall surface efficiency

(d) The total heat transfer rate

The thermal resistance for convection=1/(h*A)

where h - heat transfer coefficient and A-area

therefore thermal resistance =1/(90*0.022)

=0.5050 Celsius

fin efficiency=3.60733e+01%

the heat transfer=(Tsurface-Tfree)/R

(275-35)=240 Celsius

convert to kelvin give =240°C + 273.15= 513.15K

R-1.986kcal/kgmol K

= 513.15/1.986

= 258W/m2k

Heat Transfer: 10 square fins with conductivity 50 W/mK and side length 5.0mm are installed on a 10cm ×10cm surface whose base is kept constant at 275C. The len

Heat Transfer 10 square fins with conductivity 50 WmK and si

Solution

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