Let fx6x18x2 Then the equation of the tangent line to the gr

Let f(x)=6x+(18/x^2). Then the equation of the tangent line to the graph of f(x) at the point (2,18) is given by y=mx+b for

m=?

and

b=?

slope = 6+ 18(-2)/x
= 6-36/x at 2
=6-18= -12
y= -12x + b
18=-12*2 + b
b= 18+24
=42

m=-12, b=42