Verify that this equation results in a corrugated panel that

Verify that this equation results in a corrugated panel that is 2 inches thick.

4-A new customer has requested panels that have the same sinusoidal profile as the standard panel with the same period, but a thickness of 3 inches instead of 2.

What will the new profile equation be?

5-How many inches of raw material will be needed to manufacture 10 panels in this custom 3 inch thickness that each have a finished (corrugated) width of 35 inches? Round your answer to the nearest inch.

Solution

Answer for fiirst two bits :

Matlab code:

clc
clear
syms t
fun =@(t) log(cos(2*t));
q_1 = integral(fun,0,pi/4)
fun =@(t) 1-exp((-2)*(t));
q_2 = integral(fun,0,6)

Answer:

q_1 =

-0.5444

q_2 =

5.5000

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