Evaluate tanpi4 1 squareroot 2 1 squareroot 2 squareroot 22

Evaluate: tan(-pi/4) 1 squareroot 2 -1 -squareroot 2 -squareroot 2/2 None of the above.

Solution

solution

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tan(-pi/4)= -tan(pi/4)                          since it lies in IVth Quadrant

              = -1

option (c) is correct