Homework SourseA random sample of representatives from seven companies was
A random sample of representatives from seven companies was interviewed in order to find the number of computers they planned to order next year. The results are shown below.
8 15 33 10 9 25 12
Assuming that the population of number of computers planned to be ordered next year is normally distributed, construct a 95% confidence interval for the population mean. Express the confidence interval to 2 decimal places of accuracy.
Solution
thus, confidence interval = (9.00 to 23.00)
Hope this helps.
| Data | |||
| 8 | |||
| 15 | Bounds | ||
| 33 | Lower | 9.00 | |
| 10 | |||
| 9 | Upper | 23.00 | |
| 25 | |||
| 12 | |||
| Mean = | 16 | ||
| stdev | 9.451631 | ||
| S.E | 3.572381 | ||
| Critical Value | 1.96 |
