3 Write an assembly code that stores two different 2byte num

3. Write an assembly code that stores two different 2-byte numbers of your choice in two different memory locations of your choice (each number will actually use two memory locations because each number is 2 bytes), and that adds them and stores them in a third memory location.

Solution

Answer:

MIPS Assembly Language Code :

.zero 1
.LC0:
.string \"Addition of entered byte numbers: \"
main:
push rbp
mov rbp, rsp
sub rsp, 16
mov DWORD PTR [rbp-4], 10
mov DWORD PTR [rbp-8], 20
mov edx, DWORD PTR [rbp-4]
mov eax, DWORD PTR [rbp-8]
add eax, edx
mov DWORD PTR [rbp-12], eax
mov esi, OFFSET FLAT:.LC0
mov edi, OFFSET FLAT:std::cout
call std::basic_ostream<char, std::char_traits<char> >& std::operator<< <std::char_traits<char> >(std::basic_ostream<char, std::char_traits<char> >&, char const*)
mov rdx, rax
mov eax, DWORD PTR [rbp-12]
mov esi, eax
mov rdi, rdx
call std::basic_ostream<char, std::char_traits<char> >::operator<<(int)
mov esi, OFFSET FLAT:std::basic_ostream<char, std::char_traits<char> >& std::endl<char, std::char_traits<char> >(std::basic_ostream<char, std::char_traits<char> >&)
mov rdi, rax
call std::basic_ostream<char, std::char_traits<char> >::operator<<(std::basic_ostream<char, std::char_traits<char> >& (*)(std::basic_ostream<char, std::char_traits<char> >&))
mov eax, 0
leave
ret
__static_initialization_and_destruction_0(int, int):
push rbp
mov rbp, rsp
sub rsp, 16
mov DWORD PTR [rbp-4], edi
mov DWORD PTR [rbp-8], esi
cmp DWORD PTR [rbp-4], 1
jne .L5
cmp DWORD PTR [rbp-8], 65535
jne .L5
mov edi, OFFSET FLAT:std::__ioinit
call std::ios_base::Init::Init()
mov edx, OFFSET FLAT:__dso_handle
mov esi, OFFSET FLAT:std::__ioinit
mov edi, OFFSET FLAT:std::ios_base::Init::~Init()
call __cxa_atexit
.L5:
nop
leave
ret
push rbp
mov rbp, rsp
mov esi, 65535
mov edi, 1
call __static_initialization_and_destruction_0(int, int)
pop rbp
ret