A large Midwestern university is interested in estimating th
A large Midwestern university is interested in estimating the mean time that students spend at the student recreation center per week. A previous study indicated that the standard deviation in time is about 40 minutes per week. If the officials wish to estimate the mean time within
Solution
The 90% confidence interval for mean ? is:
[? - 1.645*?/?n , ? + 1.645*?/?n]
We want to have:
1.645*40/?n = 10
Therefore:
(1.645*40/10)^2 = 43.29 -> round this value up: n = 44
So we need 44 samples.
