Find the vertex focus and directrix of the parabola Graph th

Find the vertex, focus, and directrix of the parabola. Graph the equation.

(x-1)^2 = 4(y-2)

Std form : (x - h)² = 4p(y - k)

Vertex ( h, k) ----> ( 1 , 2)

This is an upward facing parabola:

Now 4p = 4 ---> p =1

Vetex is at ( 1,2), so focus would be above the vertex on x=1 by 1 unit .i.e. (1, 3)

The directrix is equidistant from the vertex that the focus is.: so, it is below the vertex by same distnace focus is above it : y = 1