A gas following the pV trajectory of the figure does 254256

A gas following the pV trajectory of the figure does 254.256 J of work per cycle. What is Pmax in Pascals?

P (kPa) max 100 V (cm\') 0 200 400 600 800

Solution

For the given graph, we know that the work done by the gas between Point 1 and Point 2 would be the area enclosed between the graph and the x axis between the point 1 and 2.

Now, as it is a closed cycle, the net work done would be the area inside the triangle.

That is, Area of the triangle = 254.256

or, 0.5 x 600 x 10-6 (Pm - 100) x 103 = 254.256

or, Pm = 947.52

Therefore the required value for Pmax = 947.52 kPa

A gas following the pV trajectory of the figure does 254.256 J of work per cycle. What is Pmax in Pascals? P (kPa) max 100 V (cm\') 0 200 400 600 800 SolutionFo

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