In a Hall effect experiment how is the potential difference

In a Hall effect experiment, how is the potential difference across the width related to the electric field magnitude? Explain why you chose that answer

A) The potential difference is the ratio of the field magnitude to the width.

B) The potential difference is the ratio of the width to the field magnitude.

C) The potential difference is the product of the field magnitude and the width.

Solution

According to hall effect,when a magnetic field is applied perpendicular to a current carrying conductor,a potential difference is developed between the points on opposite side of the conductor.i.e., transverse potential difference is created.

If V be the hall voltage in equilibrium then , Hall electric field E = V/d

Where d = width of the bar

From above equation V = E d

i.e.,Hall potential difference is the product of the magnitude of hall electric field and the width.