Consider a Z score of 136 taken from a standardized normal d
Consider a Z score of 1.36 taken from a standardized normal distibution. What proportion of the distribution is LESS THAN this Z value?
Consider a Z score of 1.36 taken from a standardized normal distibution. What proportion of the distribution is LESS THAN this Z value?
Solution
Given that Z<1.36.
From std normal distribution table P(Z<1.36) =0.9131
Hence as area corresponds to 1 in percent we write
91.31% are below z =1.36
