Suppose that fx 15x2 for 1 SolutionIntegrating fx Integralf
Suppose that f(x) = 1.5x^2 for -1
Solution
Integrating f(x),
Integral[f(X) dx] = 1.5x^3 / 3 = 0.5x^3, -1<x<1
and 0 otherwise.
a)
P(X>0) = 0.5(1^3) - 0.5(0^3) = 0.5 [answer]
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b)
P(X>0.5) = 0.5(1^3) - 0.5(0.5^3) = 0.4375 [answer]
***************
c)
P(-0.5<x<0.5) = 0.5(0.5)^3 - 0.5[(-0.5)^3] = 0.125 [answer]
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d)
P(X < -2) = 0, [answer]
as f(x) = 0 for x < -1.
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![Suppose that f(x) = 1.5x^2 for -1 SolutionIntegrating f(x), Integral[f(X) dx] = 1.5x^3 / 3 = 0.5x^3, -1<x<1 and 0 otherwise. a) P(X>0) = 0.5(1^3) - 0. Suppose that f(x) = 1.5x^2 for -1 SolutionIntegrating f(x), Integral[f(X) dx] = 1.5x^3 / 3 = 0.5x^3, -1<x<1 and 0 otherwise. a) P(X>0) = 0.5(1^3) - 0.](/WebImages/9/suppose-that-fx-15x2-for-1-solutionintegrating-fx-integralf-999455-1761514691-0.webp)