In the fission reaction 235U1n141Ba92Krneutrons the number o

In the fission reaction 235U+1n-141Ba+92Kr+neutrons, the number of neutrons produced is A) 2 B) 3. C) 4. D) 1 E) 0.

Solution

Sum of atomic masses in left side = 235 +1 = 236

Sum of atomic masses in right side = 141 + 92 + neutron number

                                                    = 233+ nuetron number

We know Sum of atomic masses in left side = Sum of atomic masses in right side

       236 = 233 + neutron number

Therefore neutron number = 236 - 233

                                      = 3

So, answer is \" 3 \"