12 Given PEc03 PF035 and PFE 025 find a PE and F b PE or F c

12. Given P(E^c)=0.3, P(F)=0.35, and P(F/E)= 0.25 find

a. P(E and F)

b. P(E or F)

c. P(E/F)

Solution

Given P(E^c)=0.3, P(F)=0.35, and P(F/E)= 0.25

P(E)=1-0.3=0.7

a.P(E and F)=0.7*0.35=0.245

b.P(E or F)=P(E)+P(F)-P(E and F)

=0.3+0.7-0.245

=0.755