Sue travels 5mph less than twice as fast as June Starting at

Sue travels 5mph less than twice as fast as June. Starting at the same point and traveling in the same direction, they are 80 miles apart after 4 hours. Find their speeds

Solution

Let x = J\'s speed
:
It says, \"Sue travels 5 mph less than twice as fast as June.\" So we can say:
(2x - 5) = S\'s speed
:
Using the statement: \"Starting at the same point and traveling in the same
direction, they are 80 miles apart after 4 hours.\" we can say:
:
S\'s dist traveled - J\'s distance traveled = 80
:
Dist = Time * speed
:
4(2x-5) - 4x = 80
:
8x - 20 - 4x = 80
:
8x - 4x = 80 + 20; added 20 to both sides:
:
4x = 100
:
x = 100/4
:
x = 25mph is J\'s speed
:
Using (2x - 5)
2(25) - 5 =
50 - 5 = 45 mph is S\'s speed
:
:
Check our solution by finding the distance that each has traveled:
S: 4(45) = 180 mi
J: 4(25) = 100 mi
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Difference: 80 mi