Use lisp Part 3 Defining Functions Next try defining a few s

 Use lisp  Part 3: Defining Functions  Next, try defining a few sample functions. This is Scheme code:          (define (square x) (* x x))         (define (cube x) (* x x x))         (define (fib x) (cond ((or (= 0 x)(= 1 x)) 1) (#T (+ (fib (- x 1)) (fib (- x 2))))))   Or some Lisp equivalents:          (defun square (x) (* x x))         (defun cube (x) (* x x x))         (defun fib (n)           (cond ((= n 0) 0)                 ((= n 1) 1)                 (T (+ (fib (- n 1)) (fib (- n 2))))           )         )  Show the results of defining these functions, and the results of executing these functions with some sample input data. Question: What does each function do?  Part 4: Combining Functions  In these languages, you can use a function within a function. Show an expression and output result for the square of the cube of 2. How about the fib of the square of 3? Or the square of 4 divided by 5?  Part 5: List functions  CAR, CDR, and CONS are keywords for manipulating lists of data.   Explain the output of:         (car \'(1 2 3 4))  What about this:          (cdr \'(1 2 3 4))  CAR and CDR take lists apart. CONS builds them. What is this doing? Show it!:          (cons 1 (cons 2 (cons 3 \'(4))))           MAP (Scheme) or MAPCAR (Lisp) applies a function to a list of elements and returns another list with the result. Show the results of using map/mapcar, with the arguments being:          one of the functions you defined above, and         the literal list \'(0 1 2 3 4 5 6 7 8)   (note: the Scheme syntax is clearer on this one. In Lisp, you need (mapcar #\'<function> <list>)         in scheme it\'s just (map <function> <list>)