A report gives a point estimate of 15678 with margin of erro
A report gives a point estimate of 156.78 with margin of error of 23.42. What is the corresponding confidence interval?
A report gives a point estimate of 156.78 with margin of error of 23.42. What is the corresponding confidence interval?
Solution
Confidence Interval
CI = x ± Z a/2 * (sd/ Sqrt(n))
Where,
x = Mean
sd = Standard Deviation
a = 1 - (Confidence Level/100)
Za/2 = Z-table value
CI = Confidence Interval
In Other words C.I = x ± Margin Of Error
x = 156.78, Margin Of Error = 23.42
C.I = [ 156.78 ± 23.42 ] = [ 156.78 - 23.42, 156.78 + 23.42 ] = [ 133.36, 180.2 ]
