Answer and then question is attached Please help me Thank yo

a. If two U.S. households are randomly selected, find the probability that both will have three or more vehicles. b. If two US. households are randomly selected, find the probability that neither of the two has three or more vehicles. c. If four U.S. households are randomly selected, find the probability that all four will have three or more vehicles.

Solution

a)

P(both have 3 or more) = 0.35*0.35 = 0.1225 [ANSWER]

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b)

P(neither has 3 or more) = (1-0.35)*(1-0.35) = 0.4225 [ANSWER]

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c)

P(all four have 3 or more) = 0.35^4 = 0.01500625 [ANSWER]