B115 cos 50 C115 tan 50SolutionThe base of length is 115m Th

B)115 cos 50°

C)115 tan 50°

Solution

The base of length is 115m.

The degree of acute is 50.

The base / hypothensue = cos50

Base/ hypotensue = cos50

115/hyptenuse = cos50

A) 115 divided by cos50