The table below resembles the table from the introduction to
Solution
a. Let F = aC + b where a,b are constants. We know that F = 32 when C = 0. On substituting these values of F and C in the equation, we get 32 = a*0 + c or, c = 32. Then the equation changes to F = aC + 32 . We also know that C = 25 when F = 77. On substituting these values of F and C in the equation, we get 77 = a (25) + 32 or, 25a = 77- 32 = 45. Therefore, a = 45/25 = 9/5. Then, the required equation is F = (9/5 )C + 32. or, F - 32 = 9/5 C. On multiplying both the sides by 1/9, we get C/5 = (F - 32)/ 9. We can verify this result by substituting other values of C and the given corresponding values of F from the given table.
b. On substituting C = 10 in the ewation, we get 10/5 =(F -32)/9 or, 2 = (F -32)/9 or, 18 = F - 32. Therefore F = 32+ 18 = 50. Thus the Farenheit temperature that corresponds to a Celcius rtemperature of 100 is 500 , or, when it is 100C, it is 500F
