Students 180 y AZZ38s 16161 160 140 120 100 Male Female Fem

Students 180 y» AZZ38s + 161.61 160 140 120 100 Male Female Female Male Male Male Female Female 156 152 163 167 150 155 183 Height(cm) 157 Gender 143PH

Solution

In the question, we have given a chart of students who have different height. Now we have to answer according the questions:

Serial

Male’s height

Female’s height

1

183

157

2

155

150

3

156

163

4

152

167

X= Mean: this is an average of data.

Mean X = total height/ number of males

X = 646/4 = 161.5

Range (R) = largest value – smallest value = 183- 152 = 31 cm

Variance s2 : for all data of a gender, sum the squares of differences from mean value and divide the sum by total number of data minus one

Differences

Square

183-161.5 = 21.5

462.25

155-161.5= -6.5

42.25

156-161.5 = -5.5

30.25

152-161.5=-9.5

90.25

According the definition s2 = total value/ (total numbers-1) = 625/3 = 208.33cm

Standard deviation SD = s2 = 208.33 = 14.43 cm

Standard error =SD / n, where n is the total number of data.

SE = 14.43 / 4 = 14.43/2 = 7.215

Serial

Male’s height

Female’s height

1

183

157

2

155

150

3

156

163

4

152

167

 Students 180 y» AZZ38s + 161.61 160 140 120 100 Male Female Female Male Male Male Female Female 156 152 163 167 150 155 183 Height(cm) 157 Gender 143PH Solutio
 Students 180 y» AZZ38s + 161.61 160 140 120 100 Male Female Female Male Male Male Female Female 156 152 163 167 150 155 183 Height(cm) 157 Gender 143PH Solutio

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