Students 180 y AZZ38s 16161 160 140 120 100 Male Female Fem
Solution
In the question, we have given a chart of students who have different height. Now we have to answer according the questions:
Serial
Male’s height
Female’s height
1
183
157
2
155
150
3
156
163
4
152
167
X= Mean: this is an average of data.
Mean X = total height/ number of males
X = 646/4 = 161.5
Range (R) = largest value – smallest value = 183- 152 = 31 cm
Variance s2 : for all data of a gender, sum the squares of differences from mean value and divide the sum by total number of data minus one
Differences
Square
183-161.5 = 21.5
462.25
155-161.5= -6.5
42.25
156-161.5 = -5.5
30.25
152-161.5=-9.5
90.25
According the definition s2 = total value/ (total numbers-1) = 625/3 = 208.33cm
Standard deviation SD = s2 = 208.33 = 14.43 cm
Standard error =SD / n, where n is the total number of data.
SE = 14.43 / 4 = 14.43/2 = 7.215
| Serial | Male’s height | Female’s height |
| 1 | 183 | 157 |
| 2 | 155 | 150 |
| 3 | 156 | 163 |
| 4 | 152 | 167 |

