As shown in the pedigree below a pair of first cousins I and

As shown in the pedigree below, a pair of first cousins (I and K) marry an unrelated pair of first cousins (J and L). Their children M and N produce child O.

1. Calculate the inbreeding coefficient (f) of O (express answers to 1 and 3 to three decimal places). Assume that f= 0 for all ancestors. (Hint: To help you out, I have shaded individuals who cannot contribute to autozygosity.) To show your work, use the letter names to indicate each path/loop that contributes to autozygosity. For example: path 1 = M-I-E…

2. Interpret your result. What does this value of f indicate?

3. Recalculate f for child O when f=1/2 for great-great grandmother D (f=0 for all other ancestors). Hint: After you have calculated all the loops above, you’ll adjust just the loop that includes ancester D to account for her ancestral inbreeding using the formula presented in class (and text).

As shown in the pedigree below, a pair of first cousins (I and K marry a unrelated pair of first cousin s and L). Their children M and N produce child O. 1. Calculate the inbreeding coefficient (f) of O (express answers to 1 and 3 to three decimal places). Assume that f 0 for all ancestors. (Hint: To help you out, I have shaded individuals who cannot contribute to autozyBosity.) o show your work, use the letter names to indicate each path/loop that contributes to autoz osit For example: path 1 M-1-E 2. Interpret your result. What does this value of findicate? 3. Recalculate f for child o when f-1/2 for great-great grandmother D (f 0 for all other ancestors). Hint: After you have calculated all the loops above, you\'ll adjust just the loop that includes ancester D to account for her ancestral breeding using the formula presented in class (and text)

Solution

1. Path 1:

So, the probability that a copy of gene in A makes the way down to O via E and a copy of gene in B makes the way down to O via F =( ½)ⁿ = (½)⁷=0.00781. Here n= node=7

Path 2:

Similarly like the first one the total probability in path 2 will be same that is 0.00781.

Thus inbreeding co-efficient = 0.00781+0.00781=0.01562.

2. Generally, the higher the level of inbreeding closer the coefficient of relationship approaches a value of 1 and approaches a value of 0 for individuals with remote common ancestors.

As here the value of inbreeding co-efficient is aproximately 0 so we can conclude that

3. When a common ancestor is iself inbreed the inbreeding coefficient is = (1/2)ⁿ (1+ inbreeding co-efficient of common ancestor) ,

The probability that a copy of gene in D makes the way to O = (1/2)⁷ = 0.00781

Therefore inbreeding co-efficient is = 0.00781 * (1 + 1/2 )=0.01172