Homework Soursehow to simplified using De Morgans law for the equation PBCD
how to simplified using De Morgan\'s law for the equation P=(B\'CD)+(A\'BD)+(BC\'D)+(A\'B\'C)?
Solution
Using De Morgan\'s law, considering the equation P = ( B\'CD) + ( A\'BD) + (BC\'D) + (A\'B\'C)
The values of P, when a, b, c, d values are assigned as 0 & 1, then
| A | B | C | D | P |
| 0 | 0 | 0 | 0 | 0 |
| 1 | 1 | 1 | 1 | 0 |
| 1 | 0 | 0 | 0 | 0 |
| 0 | 1 | 0 | 0 | 0 |
| 0 | 0 | 1 | 0 | 0 |
| 0 | 0 | 0 | 1 | 0 |
| 1 | 1 | 0 | 0 | 0 |
| 1 | 1 | 1 | 0 | 0 |
| 0 | 1 | 1 | 0 | 0 |
| 0 | 1 | 1 | 1 | 1 |
| 1 | 0 | 1 | 1 | 1 |
| 1 | 1 | 0 | 1 | 1 |
