Given the function fx 3x 2 Find an equation of the secant l

Given the function f(x) = 3x +2. Find an equation of the secant line passing through the points x = -1 and x = 0. (write your answer in the form y = mx + b ).

Solution

If: X₁=-1 and X₂=0

And if:

X₁=-1 ---------------> (X+1)=Y

X₂=0 ----------------> X=Y

Then:

(X+1)(X)=Y

X²+X=Y (obtaining the first derivative) ---------> Y´=2X+1

Therefore, the equation of the secant line to the function f(x) is:Y´=2X+1