Suppose two data sets x and y have identical mean and varian

Suppose two data sets x and y have identical mean and variances, but d is made up of 17 observations, and y contains 29. Which will have a larger confidence interval? Explain your answer.
Suppose two data sets x and y have identical mean and variances, but d is made up of 17 observations, and y contains 29. Which will have a larger confidence interval? Explain your answer.

Solution

Confidence Interval
CI = x ± Z a/2 * (sd/ Sqrt(n))
Where,
x = Mean
sd = Standard Deviation
a = 1 - (Confidence Level/100)
Za/2 = Z-table value
CI = Confidence Interval

Here size of n divides the stanadard deviation, higher the value of
sample size lessar the standard error [ sd/ Sqrt(n) ], thus confidence
interval is smaller. Sample size 17 will have the larger confidence interval

 Suppose two data sets x and y have identical mean and variances, but d is made up of 17 observations, and y contains 29. Which will have a larger confidence in

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