Find the time it takes for 8600 to double when invested at a
Find the time it takes for $8,600 to double when invested at an annual interest rate of 18%, compounded continuously. years Preview kila Find the time it takes for $860,000 to double when invested at an annual interest rate of 18%, compounded continuously years Preview Give your answers accurate to 4 decimal places.
Solution
We use the formula:
A=P(e)^rt
where
A=Future value
P=present value
r=rate of interest
t=time period
e=2.71828
a.
(2*8600)=8600(2.71828)^(0.18*t)
2=(2.71828)^0.18t
Taking log on both sides;
log 2=0.18t*log 2.71828
t=1/0.18[log 2/log2.71828]
=3.8508 years(Approx).
b.
(2*860,000)=860,000(2.71828)^(0.18*t)
2=(2.71828)^0.18t
Taking log on both sides;
log 2=0.18t*log 2.71828
t=1/0.18[log 2/log2.71828]
=3.8508 years(Approx).
