Wx 76 Yz 48 cm OAKLAND COMMUNITY COLLEGE AUBURN HILLS CAMPU

OAKLAND COMMUNITY COLLEGE AUBURN HILLS CAMPUS TITLE: INDEX OF REERACTION 2 CODE: PHY 1620 E10 4/02/15 ALL WORK IS TO BE ON SEPARATE DATA AND REPORT SHEETS APPARATUS: Spectrometer (on table); apparatus photos (on cart). Prism, transformer, magnifher, incandescent light, lens cleaning paper, bright line Ne or He emission source, auto collimator. (Use containers from carts with the same number as painted on the base of your spectroscope.) Black construction paper. You should try to use the same number spectroscope you used in E8 SUMMARY: You will find the index of refraction of a prism. You will use a spectrometer and the angle of minimum deviation. You must read and understand the THEORY to answer all questions. minimum deviation. N2 N1 Pr N2\' Sides AB and AC of the prism are polished. Side BC is frosted. Light is incident from point P, and s law, 1.0 sin i -nsin r1, where n is the travels to P\' along the thick lines. By Snell\'s law, 1.0 sin i -n sin r1 ,where n is the index of refraction for the material in the prism. Thus, n sin i (1) sin r1 The ray is thus deviated from its original direction by 81- Inside the prism, the ray is incident upon face AC at an angle r2. It is bent away from the normal at angle i2. The second refraction increases the deviation by angle 2. The total deviation is now 6, which is the sum of 1 and 2. s, + r1 , therefore 1_i1_r, and 2-i2-r2 Substituting into equation (2) gives =1 +2 8-2 (+ 2) (4) In the triangle DEF r1 + r2 + -180degrees In the quadrilateral AEFD, since the angles at D and E are right angles a+p=180degrees r1 + r2 =

Solution

A. n = 1.5 (2 significant digits)
B. Equilateral prism
C. angle of incidence + angle of emergence = Apex angle + deviation