lout lin 1A 100 1 kHz Solutionfrom the given data frequency

lout lin 1A 100 1 kHz

from the given data frequency f=1000hz

xc=1/(jwc)=1/(j2*3.14*1000*1*10^-6)=-j159.154 ohms

iout=[{1<0*(-j159.154)}/{100-j159.154}]

iout=(0.716-j0.45) amps

iout=0.846<-32.142 amps

magnitude=0.846

phase delay=-32.142 degrees.

$lout lin 1A 100 1 kHz Solutionfrom the given data frequency f=1000hz xc=1/(jwc)=1/(j2*3.14*1000*1*10^-6)=-j159.154 ohms iout=[{1<0*(-j159.154)}/{100-j159.15$

lout lin 1A 100 1 kHz Solutionfrom the given data frequency

Solution

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