A is 3 10 2500 63 5000 100 60000 57 B is 1 75 3 57 2500 63 A

A is ([3, 10], [2500, 6.3], [5000, 10.0], [60000, 5.7]) B is ([1, 7.5], [3, 5.7], [2500, -6.3]) A-B is (1 *5.7) + (6.3*-6.3) = 5.7 + -39.69 = 33.99 Write the java method: The dot method: public double dot(SparseVector sv), which performs the dot product of two sparse vectors. For example, if A and B are sparse vectors then A.dot(B) returns a double which is A-B Write a ToString method: toString method to properly print a sparse vector. The elements of the sparse vector must appear in increasing index order. A sparse vector with no elements prints the string empty vector. For example, if the sparse vector has the elements (1, 76.02], (4, -36.4), [5, 7.537], and (10, -2.19] then the toString method would print (10, -2.19]) then the to string method would print ([1, 76.02], [4, -36.4], [5, 7.537], [10, -2.19]).

Solution

output :3.0.

2 javaScript.

We could also use map and reduce in lieu of iteration,

or compose familiar functional primitives into a dotProduct() which returns undefined (rather than an error) when the array lengths are unmatched.

Output: