show step by step please If sin t 35 and the terminal point

show step by step please!

If sin t = 3/5 and the terminal point of t is in quadrant II, then cos t =; tan t =; cot t =; sec t =; csc t =;

Solution

in quadrant 2 sint ,csct are positive ,cost ,sect ,cott,tant are negative

sint=oppositeside/hypotenuse =y/r=3/5

adjacent side=x

by pythogorus theorem x²+y²=r²

x²+3²=5²

x²=16

x=4

cost =x/r =-4/5

tant =y/x =-3/4

cot t=x/y =-4/3

sect =r/x =-5/4

csct =r/y =5/3