Suppose that X is uniform on 2 3 and let Y X 1 Find the de

Suppose that X is uniform on [+2, 3] and let Y = |X + 1|. Find the density function of Y .

Solution

x is uniform on [2,3]

Hence pdf of x is 1, 2<=x<=3

As x is posiitive, x+1 is always positive

So Y = x+1 we can write

Y can take values from 3 to 4

Hence density funcion of Y

f(Y) = 1, 3<=y<=4

Suppose that X is uniform on [+2, 3] and let Y = |X + 1|. Find the density function of Y .Solutionx is uniform on [2,3] Hence pdf of x is 1, 2<=x<=3 As x

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