This transistor is operating in the cutoff Region Saturation

This transistor is operating in the cutoff Region Saturation Region. Active Region. Power Dissipation Region.

Solution

Given Transistor is an npn transistor

From the figure it is clear that

Base(B) is at 5V

Emitter(E) is at 7V

Collector(C) is at 10V.

This implies

Emitter Base Junction is reverse biased

and Collector Base Juncition is also reverse Biased

There fore the answer is

The given npn transitor is in Cutoff region.