A 10kg mass falls through a distance of 10 m as it falls 5 o

A 10kg mass falls through a distance of 10 m as it falls 5% of the key they it would have gained is lost to friction. at the base a roared transmits 95% of the combining key to a 20kg mass as the 20kg mass shoots upward a further 5% of the energy is lost to friction. (total losses 5 + 5 + 5 = 15%) The what height \"h\" will the 20 kg mass rise?

Solution

Data Given

Mass M1 = 10 Kg

Height through which 10 kg will fall H1 = 10m

Total Potential Energy of 10 Kg mass at 10m height PE = M1 x g x H1 = 10 x 9.81 x 10 = 981 Joules

Force F1 applied while falling of 10kg from 10m height = M1 x g = 10 x 9.81 = 98.1 N

The force F1 will be having a lose of 15% ie; only 85% of F1 will be available to lift 20kg = 981 x 0.85 = 834N

M2 x g x H2 = 834N

20 x 9.81 x H2 = 834

H2 = 834/(20*9.81)

= 4.25m

Height acheived by 20 Kg mass after considering the loses = 4.25m