when ting shafit with hsle ll ensins ar in millimeters 0000

when ting shafit with hsle ll ensins ar in millimeters 0,000 -D.do 4O.D2 ole 25 MAX an mn

Solution

Considering all dimensions in millimeters-

Upper limit of diameter of shaft = 25 + 0.000 = 25.000mm

Lower limit of diameter of shaft = 25 + (-0.004) = 24.996mm

Upper limit of diameter of hole = 25 + 0.021 = 25.021mm

Lower limit of diameter of hole = 25 + -(0) = 25.000mm

A = d2/4

Amax = (25.021)2/4

Amax = 491.698 mm2

Amin = (24.996)2/4

Amin = 490.716 mm2

 when ting shafit with hsle ll ensins ar in millimeters 0,000 -D.do 4O.D2 ole 25 MAX an mn SolutionConsidering all dimensions in millimeters- Upper limit of dia

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