when ting shafit with hsle ll ensins ar in millimeters 0000
when ting shafit with hsle ll ensins ar in millimeters 0,000 -D.do 4O.D2 ole 25 MAX an mn
Solution
Considering all dimensions in millimeters-
Upper limit of diameter of shaft = 25 + 0.000 = 25.000mm
Lower limit of diameter of shaft = 25 + (-0.004) = 24.996mm
Upper limit of diameter of hole = 25 + 0.021 = 25.021mm
Lower limit of diameter of hole = 25 + -(0) = 25.000mm
A = d2/4
Amax = (25.021)2/4
Amax = 491.698 mm2
Amin = (24.996)2/4
Amin = 490.716 mm2
