A distribution is normal and has m 90 and 10 What is the 6

A distribution is normal and has m = 90 and = 10. What is the 64th percentile?

mean = 90

standard deviation = 10

P(X <c ) = 64%

P(Z < C - mean/std) = 64%

C - 90 / 10 = invnorm(0.64)

C - 90 / 10 = 0.358

C = 10 * 0.358 + 90

= 93.58