Problem 1784 Part A The armature slender rod AB has a mass o

Problem 17.84 Part A The armature (slender rod) AB has a mass of 0.22 kg If the armature lies in the horizontal plane, and is originally at rest, determine the speed of the contact at B the instant I = 0.01 m Originally I 0.02 m. and can pivot about the pin at A Movement is controlled by the electromagnet E, which exerts a horizontal attractive force on the armature at B of Express your answer to three significant figures and include the appropriate units. Fn (0.25 10N, where 2 in meters is the 2510)N whre in meters is the gap between the armature and the magnet at any instant Eigure 1) incorrect: Try Again; 5 attempts remaining Continue Figure 1 of t 150 mm

Solution

>> As, Force, F = - m*a

where, m = Mass

and, a = acceleration = vdv/dL

As, F = 0.25*10^-3*L^-2

=> - 0.25*10^-3*L^-2 = v dv/dL

=> - 0.25*10^-3*L^-2 dL = v dv

>> Now, Integrating both sides from L = 0.02 m, v = 0 to L = 0.01 m to v = ?

=> +0.25*10^-3*| L^-1 |_0.02^0.01  = (1/2) | v² |₀^v

Simplifying,

v = 0.158 m/s .......ANSWER.......