Moist air is flowing at 05 lbs It enters a device at 75F wit

Moist air is flowing at 0.5 lb/s. It enters a device at 75F with 80% RH and is cooled to 50F. How much moisture is condensed from the moist air? How much heat removal occurs?

Solution

Given : m = 0.5 lb/s, T₁ = 75F = 23.889 ^oC , T₂ = 50 F = 10^oC, RH = 80%

From psychrometric chart, specific humidity = w₁ = 0.014 kg vapour/kg dry air

w₂ = 0.007 kg vapour/kg dry air

h₁ = 56 kJ/kg, h₂ = 27 kJ/kg

1) Moisture condensed from moist air = w₁ - w₂ = 0.007 kg vapour/kg dry air

2) Heat removal = (h₁ - h₂ )*m = 6.5771 kW.