Find the derivative y sqrt3x 2SolutionAnswer Given y3x2 So

Solution

Answer:

Given:

y=3x-2

Solution:

Now:

dy/dx=d/dx(3x-2)

y\'=d/dx{(3x-2)^1/2}

y\'=1/2(3x-2)^1/2-1 * d/dx(3x-2)

y\'=1/2(3x-2)^-1/2 *3

y\'=3/2*(3x-2)-^1/2

y\'=3/23x-2