A bag contains seven blue marbles five green marbles four bl

A bag contains seven blue marbles, five green marbles, four black marbles , and eight red marbles. If you draw one marble: a. What is the probability of not drawing a black marble? b. What is the probability that the marble you draw is green or blue? c. What is the probability of not drawing a blue or red marble? A bag contains seven blue marbles, five green marbles, four black marbles, and eight red marbles. If you draw one marble, put it back in the bag, then draw again: (4 points each) a. What is the probability of drawing a red marble each time? b. What is the probability of drawing a green marble then a blue marble? c. What is the probability of not drawing a black marble either time? A bag contains seven blue marbles, five green marbles, four black marbles, and eight red marbles. If you draw one marble, keep it out of the bag, then draw again: (4 points each) a. What is the probability of drawing a black marble each time? b. What is the probability of drawing a green marble and a blue marble? c. What is the probability of not drawing a red marble either time?

Solution

1)

a bag contains 7 blue marble,5 greenmarbles , 4 black marbles,and 8 red marbles

total number of balls are 7+5+4+8=24

if we draw a one marble

a)

probability of not drawing black marble

total number of balls without black 24-4=20

number of ways not selecting black marble is 20_c1=20

b)

probability to draw green or blue

probability of draw green is 5/24

probability to draw blue is 7/24

probability to blue or green is 5/24+7/24=12/24=1/2

c )probability not drawing blue or red

first find probability to draw blue is 7/24

probability to draw red is 8/24

probability to draw blue or red is 7/24+8/24=15/24

now probability to not draw a blue or red

1-15/24=(24-15)/24=9/24=3/8

2)

a bag contains 7 blue marble,5 greenmarbles , 4 black marbles,and 8 red marbles

total number of balls are 7+5+4+8=24

if we draw a one marble replace it then again draw a marble

a) what is the probability to draw red each time

probability to draw red in first draw is 8/24=1/3

probability to draw red in second draw is 8/24=1/3

then probability to draw red in each time is 1/3*1/3=1/9

b)

probability to green marble then a blue marble

probability to draw green marble is 5/24

probability to draw blue marble is 7/24

probability to draw a green then a blue marble is 5/24*7/24=35/24

c)

probability of not drawing black marble either time

probability to draw black marble first time 4/24=1/6

probability to drawing black marble second time 1/6

probability to draw black marble either time 1/6*1/6=1/36

probability to not draw black marble either time 1-1/36=35/36

3)

a bag contains 7 blue marble,5 greenmarbles , 4 black marbles,and 8 red marbles

total number of balls are 7+5+4+8=24

if we draw a one marble replace it then again draw a marble

a)

what is the probability to draw black each time

probability to draw black in first draw is 4/24=1/6

probability to draw black in second draw is 4/24=1/6

then probability to draw red in each time is 1/6*1/6=1/36

b)

probability of drawing green and a blue marble

probability to draw green marble is 5/24

probability to draw blue marble is 7/24

probability to draw a green then a blue marble is 5/24*7/24=35/24

c)

probability of not drawing red marble either time

probability to draw red marble first time  8/24=1/3

probability to drawing red marble second time 1/3

probability to draw red marble either time 1/3*1/3=1/9

probability to not draw black marble either time 1-1/9=8/9.