In a Si sample at 300K the fermi level is located at 035 eV
Solution
Given that, T=300K, K= 8.617x10^-5 ev/k
For Si: Nc=2.8x10^19 cm^-3 and Nv=1.04x10^19 cm^-3
The electron concentration, n=Nc*e^-(Ec-Ef)/KT
n = (2.8x10^19)*e^-(0.35)/0.026
= (2.8x10^19) (0.12191x10^-5)
n = 0.36x10^14 cm^-3
The hole concentration, p= Nv*e^-(Ef-Ev)/KT
Ef-Ev = KT ln(Nv/Na) = -0.025eV
p = (1.04x10^19) e^-(-0.025/0.026)
= 2.716 x 10^19 cm^-3
Ec-Ef = KT ln(Nv/n) = 0.026 ln[(2.8x10^19)/(0.36x10^14)]
= 0.352 eV
Ef-Ev = KT ln(Nv/p) = 0.026 ln[(1.04x10^19)/(2.71x10^19)]
= -0.0249 eV
